Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - 2-3 Solving Multi-Step Equations - Practice and Problem-Solving Exercises - Page 98: 31



Work Step by Step

We need a common denominator (bottom of the fraction) to add the numerators (tops of the fractions). Thus, we multiply $\frac{5y}{1}$ by $\frac{5}{5}$ to get $\frac{25y}{5}$. (This is legal because $\frac{5}{5}$ is equal to one). We now have: $\frac{25y}{5}$-$\frac{3}{5}$=$\frac{4}{5}$ We subtract the numerators to obtain: $\frac{25y-3}{5}$=$\frac{4}{5}$ To cancel out the two denominators, we multiply both sides of the equation by 5 to get that $25y-3=4$. We add 3 on both sides and then divide by 25 to obtain that $y=7/25$.
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