Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 780: 24

Answer

$\frac{16}{81}$

Work Step by Step

The events are independent. 4 of the 9 tiles are C's: P(C)=$\frac{4}{9}$ P(C)=$\frac{4}{9}$ P(C and C)=P(C) $\times$ P(C) P(C and C)=$\frac{4}{9}$ $\times$ $\frac{4}{9}$ P(C and C)=$\frac{16}{81}$
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