Answer
$\frac{1}{4}$
Work Step by Step
The events are independent:
3 even sides out of 6 total sides=2
P(blue even)=$\frac{3}{6}$
P(blue even)=$\frac{1}{2}$
3 even sides out of 6 total sides=
P(green even)=$\frac{3}{6}$
P(green even)=$\frac{1}{2}$
P(blue even and green even)=P(blue even) $\times$ P(green even)
P(blue even and green even)=$\frac{1}{2}$ $\times$ $\frac{1}{2}$
P(blue even and green even)=$\frac{1}{4}$
