Answer
It will always be true.
Work Step by Step
$n^{C}_{n-1}=\frac{n!}{(n-1)!(n-(n-1))!}$
$n^{C}_{n-1}=\frac{n!}{(n-1)!=\frac{n!}{(n-1)!}}$
By the definition of factorial we can write it as:
n!=n.(n-1)!
$n^{C}_{n-1}=\frac{n.(n-1)!}{(n-1)!}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 768: 64
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