## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises: 62

always

#### Work Step by Step

We know that: $_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$ $_nC_1 = \frac{n!}{(n-1)!1!}$ $\frac{ n*(n-1)!}{(n-1)!}= n$ So, it is always true

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