## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 695: 9

#### Answer

$p=3$

#### Work Step by Step

Given : $\frac{5p+2}{p} = \frac{17}{p}$ This becomes : $5p+2=17$ (After multiplying both sides of the equation with the least common denominator $p$) Thus, $5p=17-2=15$ $p=15\div5=3$ Putting $p=3$ in the initial equation, Left Hand Side, $LHS=\frac{5(3)+2}{2}=\frac{17}{3}$ Right Hand Side, $RHS=\frac{17}{3}$ Hence, $LHS=RHS$

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