## Algebra 1: Common Core (15th Edition)

The equation has one solution, $\frac{1}{3}$.
$\frac{v+2}{v}+\frac{4}{3v}=11$ $\frac{3(v+2)}{3v}+\frac{4}{3v}-\frac{11*3v}{3v}=0$ $\frac{3v+6+4-33v}{3v}=0$ $\frac{10-30v}{3v}=0$ $10-30v=0*3v$ $10-30v=0$ $30v=10$ $v=\frac{1}{3}$ Check: $\frac{1/3+2}{1/3}+4/(3\times1/3)=7+4=11$ The equation has one solution, $\frac{1}{3}$.