Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 695: 18

Answer

The equation has one solution, $\frac{1}{3}$.

Work Step by Step

$\frac{v+2}{v}+\frac{4}{3v}=11$ $\frac{3(v+2)}{3v}+\frac{4}{3v}-\frac{11*3v}{3v}=0$ $\frac{3v+6+4-33v}{3v}=0$ $\frac{10-30v}{3v}=0$ $10-30v=0*3v$ $10-30v=0$ $30v=10$ $v=\frac{1}{3}$ Check: $\frac{1/3+2}{1/3}+4/(3\times1/3)=7+4=11$ The equation has one solution, $\frac{1}{3}$.
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