Answer
$\frac{3c+8}{2c+7}$.
Work Step by Step
The given expression is
$=\frac{3c^2-4c-32}{2c^2+17c+35}\div \frac{c-4}{c+5}$
Factor.
$=\frac{(c-4)(3c+8)}{(c+5)(2c+7)}\div \frac{c-4}{c+5}$
$=\frac{(c-4)(3c+8)}{(c+5)(2c+7)}\times \frac{c+5}{c-4}$
Divide out the common factors.
$=\frac{3c+8}{2c+7}$.
