#### Answer

$2a^2b^2-3ab^3+5ab^2$

#### Work Step by Step

$(4a^3b^4-6a^2b^5+10a^2b^4) \div 2ab^2$
$=\frac{4a^3b^4}{2ab^2}-\frac{6a^2b^5}{2ab^2}+\frac{10a^2b^4}{2ab^2}$
$=2a^2b^2-3ab^3+5ab^2$
The answer is $2a^2b^2-3ab^3+5ab^2$.

Chegg costs money, GradeSaver solutions are free!

Published by
Prentice Hall

ISBN 10:
0133281140

ISBN 13:
978-0-13328-114-9

$2a^2b^2-3ab^3+5ab^2$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.