Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 683: 56



Work Step by Step

$(4a^3b^4-6a^2b^5+10a^2b^4) \div 2ab^2$ $=\frac{4a^3b^4}{2ab^2}-\frac{6a^2b^5}{2ab^2}+\frac{10a^2b^4}{2ab^2}$ $=2a^2b^2-3ab^3+5ab^2$ The answer is $2a^2b^2-3ab^3+5ab^2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.