Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Lesson Check - Page 673: 4

Answer

$\frac{4x}{(x+7)(2x+3)}$

Work Step by Step

$\frac{8x^2-12x}{x+7} \div(4x^2-9)$ $=\frac{8x^2-12x}{x+7} \times \frac{1}{4x^2-9}$ $=\frac{4x(2x-3)}{x+7}\times\frac{1}{(2x-3)(2x+3)}$ $=\frac{4x}{x+7}\times\frac{1}{2x+3}$ $=\frac{4x}{(x+7)(2x+3)}$
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