Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Lesson Check - Page 673: 2



Work Step by Step

Factor $x^{2}-8x+15$ as $(x-3)(x-5)$ It can be written as : $\frac{(x-3)(x-5)}{1}$ Factor $\frac{2x+5}{4x-12}$ as $\frac{(2x+5)}{4(x-3)}$ This becomes : $\frac{(2x+5)}{4(x-3)} \times \frac{(x-3)(x-5)}{1}$ After canceling out common factor(s), this becomes: $\frac{(2x+5)(x-5)}{4}$
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