Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 656: 55


$\sin A=\frac{5\sqrt 7}{20}$ $\cos A=\frac{3}{4}$ $\tan A=\frac{\sqrt 7}{3}$

Work Step by Step

Using the Pythagorean theorem to find the other side of the right triangle: $a^2+b^2=c^2$ $a^2+15^2=20^2$ $a=5\sqrt 7$ $\sin A=\frac{5\sqrt 7}{20}$ $\cos A=\frac{15}{20}=\frac{3}{4}$ $\tan A=\frac{5\sqrt 7}{15}=\frac{\sqrt 7}{3}$
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