Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 656: 53

$\sin A=\frac{8}{17}$ $\cos A=\frac{15}{17}$ $\tan A=\frac{8}{15}$

Using the Pythagorean theorem to find the other side of the right triangle: $a^2+b^2=c^2$ $8^2+b^2=17^2$ $b=15$ $\sin A=\frac{8}{17}$ $\cos A=\frac{15}{17}$ $\tan A=\frac{8}{15}$