Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Lesson Check - Page 636: 2



Work Step by Step

You are given $\sqrt (r+5)$=2$\sqrt (r-1)$.Solve for R: $\sqrt (r+5)$=2$\sqrt (r-1)$ -square both sides- r+5=4r-4 r+9=4r 9=3r 3=r Verify the solution by substituting r=3 into the equations.R=3 is true so 3 is the solution.
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