Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Lesson Check - Page 636: 1

Answer

x=12

Work Step by Step

You are given $\sqrt 3x$+10=16.Solve for X: $\sqrt 3x$+10=16 -subtract 10 from both sides- $\sqrt 3x$=6 -square both sides- 3x=36 x=12
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