Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Got It? - Page 634: 3



Work Step by Step

$\sqrt 7x-4=\sqrt 5x+10$ $(\sqrt 7x-4)^2=(\sqrt 5x+10)^2$ $7x-4=5x+10$ $2x=14$ $x=7$ Check: $\sqrt 7x-4=\sqrt 5x+10$ $\sqrt 7(7)-4=\sqrt 5(7)+10$ $3\sqrt 5=3\sqrt 5$
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