Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Got It? - Page 634: 2

The pendulum is about 0.825 ft long.

$2\sqrt\frac{l}{3.3}=t$ $2\sqrt\frac{l}{3.3}=1$ $\sqrt\frac{l}{3.3}=\frac{1}{2}$ $(\sqrt\frac{l}{3.3})^2=(\frac{1}{2})^2$ $\frac{l}{3.3}=\frac{1}{4}$ $l=0.825$ Check: $2\sqrt\frac{l}{3.3}=1$ $2\sqrt\frac{0.825}{3.3}=1$ $1=1$ The pendulum is about 0.825 ft long.