Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - Chapter Review - Page 69: 29



Work Step by Step

$(3c^{2}-3d)^{2}-21$ Substitute $c=3$ and $d=5$ into the equation above and solve, using order of operations: $=(3(3^{2})-3(5))^{2}-21$ $=(3(9)-15)^{2}-21$ $=(27-15)^{2}-21$ $=(12)^{2}-21$ $=144-21$ $=123$
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