Answer
$123$
Work Step by Step
$(3c^{2}-3d)^{2}-21$
Substitute $c=3$ and $d=5$ into the equation above and solve, using order of operations:
$=(3(3^{2})-3(5))^{2}-21$
$=(3(9)-15)^{2}-21$
$=(27-15)^{2}-21$
$=(12)^{2}-21$
$=144-21$
$=123$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 1 - Foundations for Algebra - Chapter Review - Page 69: 29
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