## Algebra 1: Common Core (15th Edition)

$79$
$cd^{2}+4$ Substitute $c=3$ and $d=5$ into the equation and solve. $=(3)(5^{2})+4$ Remember to solve follow the rules of PEMDAS and evaluate $5^{2}$ first, not $3\times5$. $=(3)(25)+4$ $=75+4$ $=79$