Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - Chapter Review - Page 69: 28



Work Step by Step

$cd^{2}+4$ Substitute $c=3$ and $d=5$ into the equation and solve. $=(3)(5^{2})+4$ Remember to solve follow the rules of PEMDAS and evaluate $5^{2}$ first, not $3\times5$. $=(3)(25)+4$ $=75+4$ $=79$
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