## Algebra 1: Common Core (15th Edition)

20; $14-5\times3+3^{2}$
First Equation: $14+5\times3-3^{2}$ Solve using PEMDAS (Parenthesis, Exponents, Multiplication, Division, and Subtraction). 1. Since there are no parenthesis, we will first evaluate the exponents. $3^{2}=9$ 2. Now use multiplication and evaluate $5\times3$, which equals $15$. 3. After evaluating our equation now looks like this: $14+15-9$, which equals $20$. Second Equation: $14-5\times3+3^{2}$ Solve using PEMDAS (Parenthesis, Exponents, Multiplication, Division, and Subtraction). 1. Since there are no parenthesis, we will first evaluate the exponents. $3^{2}=9$ 2. Now use multiplication and evaluate $5\times3$, which equals $15$. 3. After evaluating our equation now looks like this: $14-15+9$, which equals $8$.