## Algebra 1: Common Core (15th Edition)

A. Set x=1, y=0. If we plug these in the first expression into $(x+y)^{2}$ We get $(1+0)^{2}$ which is 1. If we plug these in the second expression, $x^{2}+y^{2}$ We get $1^{2}+0^{2}$, which is $1+0$, which is also $1$ B. Set x=1. y=2 If we plug these in the first expression into $(x+y)^{2}$ We get $(1+2)^{2}$ which is 9 If we plug these in the second expression, $x^{2}+y^{2}$ We get $1^{2}+2^{2} =1+4 = 5$ C. Set x=0, y=0 If we plug these in the first expression into $(x+y)^{2}$ We get $(0+0)^{2}$ which is 0 If we plug these in the second expression, $x^{2}+y^{2}$ We get $0^{2}+0^{2} =0+0 = 0$ D. No, when x=1 and y=2 they have different answers.