Answer
7484400 ways
Work Step by Step
The number of ways 2 objects can be placed into 1st box= $C$(12,2)
The number of ways 2 objects can be placed into 2nd box= $C$(10,2)
...
Similarly, for the last box, we have only 2 objects, so the number of ways becomes $C$(2,2)
All the boxes are distinguishable So total Number of ways = $C$(12,2)$\times$ $C$(10,2)$\times$ ....$C$(2,2) = $\frac{12!}{(2!)^{6}}$ =7484400 ways.
