Answer
302,702,400 ways to seat 14 children when there are 2 identical triplets and 3 pair of identical twins.
Work Step by Step
Total Number of arrangements of n objects if all are different = n!
If r of them are same, number of ways are given by $\frac{n!}{r!}$
There are 2 set identical triplets and 3 sets of identical twins
So number of ways is given by $\frac{14!}{3!.3!.2!.2!.2!}$ = 302702400
