## Numerical Methods for Engineers

$A_3=3.33 m^{2}$
$Q_{in}=Q_{out}$ $Q_1=Q_2+Q_3$ $40 \frac{m^{3}}{s}=20 \frac{m^{3}}{s}+Q_3$ $Q_3=20 \frac{m^{3}}{s}$ $Q=vA$ Since $Q_3=20 \frac{m^{3}}{s}$ and $v_3=6 \frac{m}{s}$ $20=6A_3$ $A_3\approx3.33 m^{2}$