Numerical Methods for Engineers

$$\begin{array}{l} \Delta T=Q / m C_{v}=14.86 K \end{array}$$ also, you can see the following image:
The mass of the air satisfies the equation $m=\frac{P V}{R T} \cdot M w T .$ $m=\frac{101.325 k P a \cdot\left(11 m \cdot 8 m \cdot 3 m-35 \cdot 0.075 m^{3}\right) \cdot 28.97 k g / k m o l}{8.314 k P a m^{3} /(k m o l K) \cdot 293 K}=314.96 k g$ The total heat absorbed by the air can be calculated $Q=35 \cdot 80 J / s \cdot 20 \cdot 60 s=3.36 \cdot 10^{6} J$ Hence $\Delta T=Q / m C_{v}=14.86 K$