Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 6 - Mechanical Properties of Metals - Questions and Problems - Page 213: 6.54b


$d = 1.45 mm$

Work Step by Step

Given: 10-mm diameter Brinell hardness indicator produced an indentation of 2.50 mm in diameter in steel alloy when load of 1000 kg was used Required: diameter of indentation to yield hardness of 300 HB when 500-kg load is used Solution: Using equation for HB in Table 6.5: $d = \sqrt D^{2} - [D - \frac{2P}{(HB)πD}]^{2} = \sqrt (10 mm)^{2} - [(10 mm) - \frac{2 (500 kg)}{(300)π(10 mm)}]^{2} = 1.45 mm$
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