#### Answer

$HB = 200.48 \approx 200 $

#### Work Step by Step

Given:
10-mm diameter Brinell hardness indicator produced an indentation of 2.50 mm in diameter in steel alloy when load of 1000 kg was used
Required:
HB of the metal
Solution:
Using the equation for HB in Table 6.5:
$HB = \frac{2P}{πD[D - \sqrt D^{2}-d^{2}]} = \frac{2(1000 kg)}{π(10 mm)[(10 mm) - \sqrt (10 mm)^{2}-(2.50 mm)^{2}]} = 200.48 \approx 200 $