Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 6 - Mechanical Properties of Metals - Questions and Problems - Page 213: 6.54a


$HB = 200.48 \approx 200 $

Work Step by Step

Given: 10-mm diameter Brinell hardness indicator produced an indentation of 2.50 mm in diameter in steel alloy when load of 1000 kg was used Required: HB of the metal Solution: Using the equation for HB in Table 6.5: $HB = \frac{2P}{πD[D - \sqrt D^{2}-d^{2}]} = \frac{2(1000 kg)}{π(10 mm)[(10 mm) - \sqrt (10 mm)^{2}-(2.50 mm)^{2}]} = 200.48 \approx 200 $
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