Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 2 - Atomic Structure and Interatomic Bonding - Questions and Problems - Page 48: 2.5b



Work Step by Step

We have 453.6 g/lbm so $1lb.mol=(453.6 g/lbm)(6.022\times10^{23} atoms/g.mol)=2.73\times10^{26}atoms/lb.mol$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.