Answer
$1.10\times{10}^{-8}N
$
Work Step by Step
According to equation 2.4, the sum of the attractive and repulsive forces is zero.
$F_{R}=-F_{A} = -(1.10\times{10}^{-8}N)=-1.10\times{10}^{-8}N
$
Materials Science and Engineering: An Introduction
by Callister, William D.; Rethwisch, David G.
Published by
Wiley
ISBN 10:
1118324579
ISBN 13:
978-1-11832-457-8
Chapter 2 - Atomic Structure and Interatomic Bonding - Questions and Problems - Page 48: 2.16b
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