Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 19 - Thermal Properties - Questions and Problems - Page 801: 19.25c

Answer

$σ = +58.2 MPa$, tensile

Work Step by Step

Given: As in Part (a), but now $T_{f} = -15 °C$ Required: type and magnitude of stress Solution: $σ = Eα_{l}(T_{0} - T_{f}) = (97 \times 10^{3} MPa)(20.0 \times 10^{-6} (°C)^{-1})(15 °C - (-15°C)) \\ = +58.2 MPa$ Since the computed value is positive, the stress is tensile.
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