Answer
$\frac{dQ}{dt}= 2.88 \times 10^{9} J/h$
Work Step by Step
Given:
brass 7.5 mm (0.30 in.) thick
$q = 1.6 \times 10^{6} \frac{W}{m^{2}}$
area = $0.5 m^{2} (5.4 ft^{2})$
Required:
heat loss per hour
Solution:
Let $\frac{dQ}{dt} = qAt$,
$\frac{dQ}{dt} = (1.6 \times 10^{6} \frac{J}{ s.m^{2}})(0.5 m^{2})(60 s/min)(60min/hr) = 2.88 \times 10^{9} J/h$
