## Materials Science and Engineering: An Introduction

Published by Wiley

# Chapter 18 - Electrical Properties - Questions and Problems - Page 782: 18.54b

#### Answer

$D = 4.89 \times 10^{-6} C/m^{2}$

#### Work Step by Step

Given: Polarization, P, of a dielectric material positioned within a parallel-plate capacitor is to be $4.0 \times 10^{-6} C/m^{2}$, and an electric field of $10^{5}$ V/m is applied. Required: dielectric displacement, D Using Equation 18.31: $D = ε_{0}E + P = (8.85 \times 10^{-12} F/m)(10^{5} V/m) + (4.0 \times 10^{-6} C/m^{2}) = 4.89 \times 10^{-6} C/m^{2}$

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