Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 782: 18.54a


$ε_{r} = 5.52$

Work Step by Step

Given: Polarization, P, of a dielectric material positioned within a parallel-plate capacitor is to be $4.0 \times 10^{-6} C/m^{2}$. Required: dielectric constant if an electric field of $10^{5} V/m$ is applied. Solution: Using Equation 18.32: $ε_{r} = \frac{P}{ε_{0}E} + 1 = \frac{(4.0 \times 10^{-6} C/m^{2})}{(8.85 \times 10^{-12} F/m) (10^{5} V/m)} + 1 = 5.52$
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