Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 781: 18.42


$B_{z} = 0.74\ T$

Work Step by Step

Given: A metal alloy is known to have electrical conductivity and electron mobility values of $1.2 \times 10^{7} (Ω-m)^{-1}$ and $0.0050 m^{2}/V-s$, respectively. A current of 40 A passes through a specimen of this alloy that is 35 mm thick. Required: What magnetic field would need to be imposed to yield a Hall voltage of $-3.5 \times 10^{-7} V$? Solution: Using a combination of Equations 18.18 and 18.20b: $B_{z} = \frac{|V_{H}|d}{I_{x}R_{H}} = \frac{|V_{H}|dσ}{I_{x}μ_{e}}$ $B_{z} = \frac{|(-3.5 \times 10^{-7} V)|(35 \times 10^{-3} m)(1.2 \times 10^{7} (Ω-m)^{-1})}{(40 A)(0.0050 m^{2}/V-s)} = 0.74\ Tesla $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.