Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 778: 18.5d


$E = 8.0 \times 10^{-3} V/m$

Work Step by Step

Given: For an aluminum wire 5 mm (0.20 in.) in diameter and 5 m (200 in.) in length, the potential drop across the ends of the wire is 0.04 V Required: The magnitude of the electric field across the ends of the wire. Solution: $E = \frac{V}{l} = \frac{0.04 V}{5 m} = 8.0 \times 10^{-3} V/m$
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