Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 778: 18.5b

Answer

$I = 5.97 A$

Work Step by Step

Required: Using the data in Table 18.1, compute the resistance of an aluminum wire 5 mm (0.20 in.) in diameter and 5 m (200 in.) in length We are asked to find the current flow if the potential drop across the ends of the wire is 0.04 V. Solution: From Item 18.5a, $R= 6.70 \times 10^{-3} Ω$ Combining Equations 18.2 and 18.4 and using $σ = 3.8 \times 10^{7} (Ω−m)^{-1}$ from table 18.1, we find: $I = \frac{V}{R} = \frac{0.04 V}{6.70 \times 10^{-3} Ω} = 5.97 A$
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