Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 17 - Corrosion and Degradation of Materials - Questions and Problems - Page 721: 17.11


t = 4.6 x $10^{4}$ h = 5.25 yr $\approx$ 5.3 yr

Work Step by Step

Rearranging Equation 17.23 to get time t, t = $\frac{KW}{pA(CPR)}$ Using the given values and substituting it to the above equation: Use CPR value of 87.6: t = $\frac{(87.6)(7.6 \times 10^{6} mg)}{(4.5 g/cm^{3})(800 cm^{2})(4 mm/yr)}$ t = 4.6 x $10^{4}$ h = 5.25 yr $\approx$ 5.3 yr
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