Answer
In this question , we are asked to find the velocity,
and we know that Mass flow rate = density $\times$ area $\times$ velocity.
Here in the question we are given the temperature and quality (x) for 134a refrigerator, so we look into the table at -15 F or -26 C 9 (approx) and we get the specific volume by the expression
v = $v_{f}$ + (x)( $v_{g}$ - $v_{f}$ )
putting value of vf and vg from the table at -26 C , and uisng x=.05. we get v= 0.01102308.
and we know density is the reciprocal of specific vloume,
so density = 1/v
89.04 kg/$m^{3}$.
now putting the values of area in metres , and mass flow rate in kg/sec , we get velocity from above expression as
velocity = 16.1 m/sec.
Work Step by Step
In this question , we are asked to find the velocity,
and we know that Mass flow rate = density $\times$ area $\times$ velocity.
Here in the question we are given the temperature and quality (x) for 134a refrigerator, so we look into the table at -15 F or -26 C 9 (approx) and we get the specific volume by the expression
v = $v_{f}$ + (x)( $v_{g}$ - $v_{f}$ )
putting value of vf and vg from the table at -26 C , and uisng x=.05. we get v= 0.01102308.
and we know density is the reciprocal of specific vloume,
so density = 1/v
89.04 kg/$m^{3}$.
now putting the values of area in metres , and mass flow rate in kg/sec , we get velocity from above expression as
velocity = 16.1 m/sec.
