Answer
$$
F=9.24 \mathrm{kN}
$$
Work Step by Step
$$
\begin{aligned}
↺+M_R=\Sigma M_C ; \quad 12 & =\left(F \cos 30^{\circ}\right)(0.3)+8(1.2) \\
F & =9.238 \mathrm{kN}\\&=9.24 \mathrm{kN}
\end{aligned}
$$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 4 - Force System Resultants - Section 4.6 - Moment of a Couple - Problems - Page 162: 76
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