Answer
$$
M_C=22.5 \mathrm{~N} \cdot \mathrm{m}↻
$$
Work Step by Step
$$
\begin{aligned}
& ↺+M_c=\Sigma M ; \quad M_c=-75(0.15+0.15) \\
& =-22.5 \mathrm{~N} \cdot \mathrm{m}=22.5 \mathrm{~N} \cdot \mathrm{m} \text { ↻ } \\
&
\end{aligned}
$$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 4 - Force System Resultants - Section 4.6 - Moment of a Couple - Problems - Page 162: 74
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
