Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 3 - Equilibrium of a Particle - Section 3.3 - Coplanar Force Systems - Problems: 3

Answer

$\theta=82.2^{\circ}$ $F=3.96kN$

Work Step by Step

First we will sum the forces horizontally $(\rightarrow +) \sum \overrightarrow{F}_{x} =0 $ $F\sin\theta−4\cos60^{\circ}-8\cos30^{\circ}=0$ Now we will sum the forces vertically $(\uparrow +) \sum \overrightarrow{F}_{y} =0 $ $8\sin30^{\circ}-4\sin60^{\circ}−F\cos\theta=0$ Solving the system of two equations, we obtain : $\theta=82.2^{\circ}$ $F=3.96kN$
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