Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 3 - Equilibrium of a Particle - Section 3.3 - Coplanar Force Systems - Problems: 2

Answer

$\theta=4.69^{\circ}$ $F_1=4.31kN$

Work Step by Step

First we will sum the forces horizontally $(\rightarrow +) \sum \overrightarrow{F}_{x} =0 $ $6\sin70^{\circ}+F_1\cos\theta−5\cos30^{\circ}−4/5(7)=0$ Now we will sum the forces vertically $(\uparrow +) \sum \overrightarrow{F}_{y} =0 $ $6\cos70^{\circ}+5\sin30^{\circ}−F_1\sin\theta−3/5(7)=0$ Solving the system of two equations, we obtain : $\theta=4.69^{\circ}$ $F_1=4.31kN$
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