Answer
$W_B=18.3 \mathrm{lb}$
Work Step by Step
$$
\theta=\sin ^{-1}\left(\frac{0.5}{1.25}\right)=23.58^{\circ}
$$
Equations of Equilibrium:
$$
\begin{array}{cc}
\pm \Sigma F_x=0 ; & 10 \sin 23.58^{\circ}-10 \sin 23.58^{\circ}=0 \quad \text { } \\
+\uparrow \Sigma F_y=0 ; & 2(10) \cos 23.58^{\circ}-W_B=0 \\
W_B=18.3 \mathrm{lb}
\end{array}
$$
