Answer
$T_{AB}=134lb$
$T_{CD}=106lb$
The attachment at points C and D produces the least amount of tension.
Work Step by Step
We can find the required tension as follows:
$cos\theta=\frac{2}{3}$
$\implies \theta=48.2$
The sum of forces in the y-direction is given as
$\Sigma F_y=0$
$\implies 200-2T_{AB} sin\theta=0$
$\implies T_{AB}=134lb$
Now, for the second attachment at C and D
$cos\phi=\frac{1}{3}$
$\implies \phi=70.5$
The sum of forces in the y-direction is given as
$\Sigma F_y=0$
$\implies 200-2T_{CD}sin\phi=0$
$\implies T_{CD}=106lb$
Thus, we can see that the attachment at points C and D produces the least amount of tension.
