Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 3 - Equilibrium of a Particle - Section 3.3 - Coplanar Force Systems - Problems - Page 100: 16



Work Step by Step

The required mass of each of the two cylinders can be determined as follows: $T=K\Delta x$ We plug in the known values to obtain: $T=100(2\sqrt{2}-2.5)=32.8N$ Now $\Sigma F_y=0$ $\implies Tsin\theta-mg=0$ $\implies 32.8N sin(45)-m(9.81)=0$ This simplifies to: $m=2.37Kg$
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