Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 22 - Vibrations - Section 22.6 - Electrical Circuit Analogs - Problems - Page 675: 53



Work Step by Step

We can find the required angular velocity as follows: $K=\frac{mg}{\delta}$ $\implies K=\frac{25\times 9.81}{0.05}=4905N/m$ Now $\omega=\sqrt{\frac{K}{m}}$ We plug in the known values to obtain: $\implies \omega_n=\sqrt{\frac{4905}{25}}$ $\implies \omega_n=14rad/s$
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