#### Answer

$F_{1}x = 141N$
$F_{1}y = 141N$
$F_{2}y = -130N$
$F_{2}y = 75N$

#### Work Step by Step

We determine the force components:
$F_{1}x =200\times \sin 45 ° = 141N$
$F_{1}y = 200 \times \cos 45 ° =141N$
$F_{2}y =-150 \times \cos 30 ° = -130N$
$F_{2}y = 150 \times \sin 30 ° = 75N$