Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 2 - Force Vectors - Section 2.4 - Addition of a System of Coplanar Forces - Problems - Page 41: 43

Answer

FRx = -162.83 N FRy = -520.94 N FR = 546 N Angle = 253

Work Step by Step

Summation of X components Of All the Forces. X component Of Resultant Force = F1x + F2x + F3x (we are using Sin because all angles are wrt to Verticle axis) FRx = 4/5(850) - 625 sin 30° - 750 sin 45° FRx = -162.83 N Summation of Y components Of All the Forces. Y component Of Resultant Force = F1y + F2y + F3y (we are using Cos because all angles are wrt to Verticle axis) FRy = - 3/5(850) - 625 cos 30° + 750 cos 45° FRy = -520.94 N FR = {(-162.83)^2 + (-520.94)^2}^1/2 FR = 546 N Angle = tan-1 (520.94/162.83) Angle = 72.64° Total Angle Wrt +X-axis = 180+72.64 = 253
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