#### Answer

$F_{1} = (900\hat{i})$
$F_{2} = (530\hat{i} + 530\hat{j})$
$F_{3} = (520\hat{i} - 390\hat{j})$

#### Work Step by Step

We resolve the forces:
$F_{1} = (900\hat{i})$
$F_{2} = (750 \times \cos 45 ° \hat{i} + 750 \times \sin 45 ° \hat {j}) = (530\hat{i} + 530\hat{j})$
$F_{3} = (650 \times 4/5\hat{i} + 650 \times 3/5 -\hat{j})=(520\hat{i} - 390\hat{j})$