## Engineering Mechanics: Statics & Dynamics (14th Edition)

$F_{R}=217N$ $\theta = 87°$
Projecting both forces on the x axis: $F_{R}x = 200 \times \sin(45°) - 150 \times \cos (30°) = 11.518 N$ Projecting both forces on the y axis: $F_{R} = 200 \times \cos(40°) + 150 \times \sin (30°) = 216.42N$ The magnitude of the force is obtained: $F_{R} = \sqrt (11.518^{2} + 216.42^{2}) = 216.73 N \approx 217 N$ The direction relative to x axis is obtained: $\theta = \tan^{-1} (\frac{F_{R}y}{F_{R}x}) = 86.95° \approx 87°$